Solutions to 2-variable equations: substitution (old)

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About this video

Sal checks whether the point (3, -4) is a solution to 5x + 2y = 7 by substituting x = 3 and y = -4: 15 + (-8) = 7, so it is. He notes you could also graph the line and see if the point is on it, but substitution is always exact.

You'll be able to

  • test whether an ordered pair is a solution to a two-variable equation by substituting.
  • explain why substitution is more exact than reading a graph.

Key words

solution
An (x, y) pair that makes the equation true.
substitute
Replace a variable with a number.
ordered pair
A point written (x, y), with x first and y second.
Transcript

Is 3 comma negative 4 a solution to the equation 5x plus 2y is equal to 7? So they're saying, does x equal 3, y equal negative 4, satisfy this equation, or this relationship right here? So one way to do it is just to substitute x is equal to 3 and y equals negative 4 into this and see if 5 times x plus 2 times y does indeed equal 7.

So we have 5 times 3 plus 2 times negative 4. This is equal to 15. 15 plus negative 8, which does indeed equal 7. So it does satisfy the equation. So it is on the line. It is a solution. x equals 3, y equals negative 4 is a solution to this equation. So we've essentially answered our question.

It is. Now, another way to do it, and I'm not going to go into the details here, is you could actually graph the line. So maybe the line might look something like this, I'm not going to do it in detail. And you see, if you have a very good drawing of it, you see whether the point lies on the line.

If the point, when you graph the point, does lie on the line, it would be a solution. If the point somehow ends up not being on the line then you'd know it isn't a solution. But to do this, you would have to have a very good drawing and so you could very precisely determine whether it's on the line.

If you do the substitution method, if you just substitute the values into the equation and see if it comes out mathematically, this will always be exact. So this is all we really had to do in this example. So it definitely is a solution to the equation.

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