Visually verifying a solution to a system

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Maths8th grade math (TX TEKS)1:152 check-ins

About this video

Two lines, y = -x - 7 and y = 1/2x - 1, are graphed. At x = -8 the blue line has y = 1 and the brown line has y = -5. Because the y-values are different, the lines don't meet there, so x = -8 is not a solution of the system.

You'll be able to

  • read the y-value of a line at a given x from a graph.
  • explain that a solution needs both lines to have the same y-value at the same x.

Key words

system of linear equations
Two or more linear equations considered together.
solution
An x and y that make both equations true; on a graph, where the lines intersect.
intersect
Cross or meet at the same point.
Transcript

- [Instructor] We're told the system of linear equations below is graphed on the coordinate grid. Okay, we see that. Then, it says: What is the value of y equals -x - 7 when x is equal to -8. So the graph y equals -x - 7, that's this blue line here, and they tell us, right?

That the point -8, 1 is on that line. So when x is equal to -8, y is equal to 1. So we could type that in. And then, they ask us: What is the y-value of the bronze line or the brown line here, y is equal to 1/2x - 1 when x is equal to -8. So we don't even have to compute it.

We see when x is equal to -8, we get y is equal to -5, so we put -5 there. And then, they say: Is x equal -8 a solution? Well, the only way that x equals -8 would be a solution is if the y value of those lines when x equals -8 were the same, but they're clearly not.

And in fact, we would see it visually. If it was a solution, the two lines would intersect at that point but they don't. There's actually two different points here. They don't overlap. So this is not a solution and we're done.

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