Vector form of the multivariable chain rule

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About this video

The multivariable chain rule can be written in vector form. If v(t) = (x(t), y(t)) is a vector-valued function, then the derivative of f(v(t)) is the gradient of f evaluated at v(t), dotted with the vector derivative v'(t). This mirrors the single-variable chain rule f'(g(t)) g'(t) and extends to functions of many variables, such as 100.

You'll be able to

  • write the derivative of a vector-valued function by differentiating each component.
  • recognise the multivariable chain rule as a dot product of the gradient and v'(t).
  • compare the vector form of the chain rule with the single-variable chain rule.
  • explain how the vector form generalises to functions with many input variables.

Key words

vector-valued function
A function that takes a single number t and outputs a vector, such as v(t) = (x(t), y(t)).
vector derivative v'(t)
The vector of the derivatives of each component of v(t).
gradient
The vector of partial derivatives of f; it acts as the derivative of a multivariable scalar function.
dot product
Multiply matching components of two vectors and add the results.
Transcript

- [Voiceover] So in the last couple of videos, I talked about the multi-variable chain rule, which I have up here, and if you haven't seen those go take a look. Here and I want to write it out in vector notation, and this helps us generalize it a little bit when the intermediary space is a little bit higher dimensional.

So, instead of writing X of T and Y of T as separate functions, and just trying to emphasize "oh they have the same input space, and whatever X takes in that's the same number Y takes in." It's better and a little bit cleaner if we say there's a vector valued function that takes in a single number "T," then it outputs some kind of vector.

In this case you could say the components of V are X of T and Y of T, and that's fine. But I want to talk about what this looks like if we start writing everything in vector notation, and just since we see DX/DT here and DY/DT here, you might start thinking, "oh we should take the derivative of that vector valued function."

The derivative of V, with respect to T, and when we compute this it's nothing more than taking the derivatives of each component. So in this case, the derivative of X, so you'd write DX/DT, and the derivative of Y, DY/DT. This is the vector value derivative. And now you might start to notice something here.

Okay so we've got one of those components multiplied by a certain value and another component multiplied by a certain value, you might recognize this as a dot product. This would be the dot product between the vector that contains the derivatives, the partial derivatives, partial of F with respect to Y, partial of F with respect to X, oh, whoops, don't know why I wrote it that way, but up here that's with respect to X, and then here to Y.

So this whole thing, we're taking the dot product with the vector that contains ordinary derivative DX/DT and ordinary derivative DY/DT. And of course both of these are special vectors, they're not just random, the left one, that's the gradient of F, and the right vector here that's what we just wrote that's the derivative of V with respect to T, just for being quick I'm gonna write that as V prime of T.

That's saying completely the same thing as VDVT, and this right here is another way to write the multi-variable chain rule, and maybe if you were being a little bit more exact you would emphasize that when you take the gradient of F the thing that you input into it is the output of that vector valued function, you know you're throwing in X of T and Y of T, so you might emphasize that you take in that as an input, and then you multiply it by the derivative, the vector valued derivative of V of T.

And when I say multiply, I mean dot product, right, these are vectors and you're taking the dot product, it should seem very familiar to, you know, the single-variable chain rule. And just to remind us I'll throw it up here, if you take the derivative of composition of two single-variable functions F of G, you take the derivative of the outside F prime, and throw in G, throw in what was the interior function, and you multiply it by the derivative of that interior function, G prime of T.

And this is super helpful in single-variable calculus for computing a lot of derivatives, and over here it has a very similar form right? The gradient which really serves the function of the true extension of the derivative for multi-variable functions for scalar valued multi-variable functions at least. You take that derivative and throw in the inner function, which just happens to be a vector valued function.

You throw it in there, and then you multiply it by the derivative of that, but multiplying vectors in this context means taking the dot product of the two, and this could mean if you have a function with a whole bunch of different variables, let's say you have some F of X, or not F of X, F of X1 and X2 and it takes in a whole bunch of variables that it goes out to X100.

And then what you throw into it is the vector value function that's vector valued, takes in a single variable, and in order to be able to compose them it's gonna have a whole bunch of intermediary functions, and you can write it as X1, X2, X3, all the way up to X100 , and these are all functions at this point.

These are component functions of your vector valued V. This expression still makes sense, right? You can still take the gradient of F, it's gonna have 100 components, you can plug in any vector, any set of 100 different numbers, and in particular the output of a vector valued function with 100 different components is gonna work, and then you take the dot product with the derivative of this. That's the more general version of the multi-variable chain rule, and then the cool way about writing it like this, you can interpret it in terms of the directional derivative, and I think I'll do that in the next video, so, that's a certain way to interpret this with a directional derivative.

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